Albert had an equal number of strawberry biscuits, cream biscuits and chocolate biscuits. After he ate 20 strawberry biscuits, some cream biscuits and chocolate biscuits, there were 54 biscuits left. The number of cream biscuits he ate was thrice the number of chocolate biscuits he ate. The number of cream biscuits left was 14 more than the number of strawberry biscuits left. How many strawberry biscuits were there at first?
|
Strawberry biscuits |
Cream biscuits |
Chocolate biscuits |
Total biscuits |
Before |
1 p + 20 |
1 p + 3 u + 14 |
1 p + 3 u + 14 |
|
Change |
- 20 |
- 3 u |
- 1 u |
|
After |
1 p |
1 p + 14 |
1 p + 14 + 1 u |
54 |
Number of cream biscuits and strawberry biscuits was equal at first.
1 p + 3 u + 14 = 1 p + 20
3 u = 20 - 14
3 u = 6
1 u = 6 ÷ 3 = 2
Total number of biscuits in the end
= 1 p + 1 p + 14 + 1 p + 14 + 2
= 1 p + 1 p + 1 p + 14 + 14 + 2
= 3 p + 30
3 p + 30 = 54
3 p = 54 - 30
3 p = 24
1 p = 24 ÷ 3 = 8
Number of strawberry biscuits at first
= 1 p + 20
= 8 + 20
= 28
Answer(s): 28