Vincent had an equal number of vanila wafers, chocolate wafers and butter wafers. After he ate 28 vanila wafers, some chocolate wafers and butter wafers, there were 68 wafers left. The number of chocolate wafers he ate was twice the number of butter wafers he ate. The number of chocolate wafers left was 22 more than the number of vanila wafers left. How many vanila wafers were there at first?

	Vanila wafers	Chocolate wafers	Butter wafers	Total wafers
Before	1 p + 28	1 p + 2 u + 22	1 p + 2 u + 22
Change	- 28	- 2 u	- 1 u
After	1 p	1 p + 22	1 p + 22 + 1 u	68

Number of chocolate wafers and vanila wafers was equal at first.

1 p + 2 u + 22 = 1 p + 28
2 u = 28 - 22
2 u = 6

1 u = 6 ÷ 2 = 3

Total number of wafers in the end
= 1 p + 1 p + 22 + 1 p + 22 + 3
= 1 p + 1 p + 1 p + 22 + 22 + 3
= 3 p + 47

3 p + 47 = 68
3 p = 68 - 47
3 p = 21

1 p = 21 ÷ 3 = 7

Number of vanila wafers at first
= 1 p + 28
= 7 + 28
= 35

Answer(s): 35