Jeremy had an equal number of chocolate muffins, vanila muffins and butter muffins. After he ate 50 chocolate muffins, some vanila muffins and butter muffins, there were 43 muffins left. The number of vanila muffins he ate was four times the number of butter muffins he ate. The number of vanila muffins left was 14 more than the number of chocolate muffins left. How many chocolate muffins were there at first?
|
Chocolate muffins |
Vanila muffins |
Butter muffins |
Total muffins |
Before |
1 p + 50 |
1 p + 4 u + 14 |
1 p + 4 u + 14 |
|
Change |
- 50 |
- 4 u |
- 1 u |
|
After |
1 p |
1 p + 14 |
1 p + 14 + 1 u |
43 |
Number of vanila muffins and chocolate muffins was equal at first.
1 p + 4 u + 14 = 1 p + 50
4 u = 50 - 14
4 u = 36
1 u = 36 ÷ 4 = 9
Total number of muffins in the end
= 1 p + 1 p + 14 + 1 p + 14 + 9
= 1 p + 1 p + 1 p + 14 + 14 + 9
= 3 p + 37
3 p + 37 = 43
3 p = 43 - 37
3 p = 6
1 p = 6 ÷ 3 = 2
Number of chocolate muffins at first
= 1 p + 50
= 2 + 50
= 52
Answer(s): 52