Ethan had an equal number of butter wafers, chocolate wafers and vanila wafers. After he ate 32 butter wafers, some chocolate wafers and vanila wafers, there were 76 wafers left. The number of chocolate wafers he ate was twice the number of vanila wafers he ate. The number of chocolate wafers left was 16 more than the number of butter wafers left. How many butter wafers were there at first?
|
Butter wafers |
Chocolate wafers |
Vanila wafers |
Total wafers |
Before |
1 p + 32 |
1 p + 2 u + 16 |
1 p + 2 u + 16 |
|
Change |
- 32 |
- 2 u |
- 1 u |
|
After |
1 p |
1 p + 16 |
1 p + 16 + 1 u |
76 |
Number of chocolate wafers and butter wafers was equal at first.
1 p + 2 u + 16 = 1 p + 32
2 u = 32 - 16
2 u = 16
1 u = 16 ÷ 2 = 8
Total number of wafers in the end
= 1 p + 1 p + 16 + 1 p + 16 + 8
= 1 p + 1 p + 1 p + 16 + 16 + 8
= 3 p + 40
3 p + 40 = 76
3 p = 76 - 40
3 p = 36
1 p = 36 ÷ 3 = 12
Number of butter wafers at first
= 1 p + 32
= 12 + 32
= 44
Answer(s): 44