Cole had an equal number of cream wafers, blueberry wafers and chocolate wafers. After he ate 49 cream wafers, some blueberry wafers and chocolate wafers, there were 85 wafers left. The number of blueberry wafers he ate was four times the number of chocolate wafers he ate. The number of blueberry wafers left was 21 more than the number of cream wafers left. How many cream wafers were there at first?
|
Cream wafers |
Blueberry wafers |
Chocolate wafers |
Total wafers |
Before |
1 p + 49 |
1 p + 4 u + 21 |
1 p + 4 u + 21 |
|
Change |
- 49 |
- 4 u |
- 1 u |
|
After |
1 p |
1 p + 21 |
1 p + 21 + 1 u |
85 |
Number of blueberry wafers and cream wafers was equal at first.
1 p + 4 u + 21 = 1 p + 49
4 u = 49 - 21
4 u = 28
1 u = 28 ÷ 4 = 7
Total number of wafers in the end
= 1 p + 1 p + 21 + 1 p + 21 + 7
= 1 p + 1 p + 1 p + 21 + 21 + 7
= 3 p + 49
3 p + 49 = 85
3 p = 85 - 49
3 p = 36
1 p = 36 ÷ 3 = 12
Number of cream wafers at first
= 1 p + 49
= 12 + 49
= 61
Answer(s): 61