Seth had an equal number of blueberry doughnuts, cream doughnuts and butter doughnuts. After he ate 41 blueberry doughnuts, some cream doughnuts and butter doughnuts, there were 79 doughnuts left. The number of cream doughnuts he ate was twice the number of butter doughnuts he ate. The number of cream doughnuts left was 17 more than the number of blueberry doughnuts left. How many blueberry doughnuts were there at first?

	Blueberry doughnuts	Cream doughnuts	Butter doughnuts	Total doughnuts
Before	1 p + 41	1 p + 2 u + 17	1 p + 2 u + 17
Change	- 41	- 2 u	- 1 u
After	1 p	1 p + 17	1 p + 17 + 1 u	79

Number of cream doughnuts and blueberry doughnuts was equal at first.

1 p + 2 u + 17 = 1 p + 41
2 u = 41 - 17
2 u = 24

1 u = 24 ÷ 2 = 12

Total number of doughnuts in the end
= 1 p + 1 p + 17 + 1 p + 17 + 12
= 1 p + 1 p + 1 p + 17 + 17 + 12
= 3 p + 46

3 p + 46 = 79
3 p = 79 - 46
3 p = 33

1 p = 33 ÷ 3 = 11

Number of blueberry doughnuts at first
= 1 p + 41
= 11 + 41
= 52

Answer(s): 52