Xavier had an equal number of chocolate wafers, vanila wafers and cream wafers. After he ate 23 chocolate wafers, some vanila wafers and cream wafers, there were 35 wafers left. The number of vanila wafers he ate was thrice the number of cream wafers he ate. The number of vanila wafers left was 11 more than the number of chocolate wafers left. How many chocolate wafers were there at first?

	Chocolate wafers	Vanila wafers	Cream wafers	Total wafers
Before	1 p + 23	1 p + 3 u + 11	1 p + 3 u + 11
Change	- 23	- 3 u	- 1 u
After	1 p	1 p + 11	1 p + 11 + 1 u	35

Number of vanila wafers and chocolate wafers was equal at first.

1 p + 3 u + 11 = 1 p + 23
3 u = 23 - 11
3 u = 12

1 u = 12 ÷ 3 = 4

Total number of wafers in the end
= 1 p + 1 p + 11 + 1 p + 11 + 4
= 1 p + 1 p + 1 p + 11 + 11 + 4
= 3 p + 26

3 p + 26 = 35
3 p = 35 - 26
3 p = 9

1 p = 9 ÷ 3 = 3

Number of chocolate wafers at first
= 1 p + 23
= 3 + 23
= 26

Answer(s): 26