Helen spent $84 on a blazer. She spent
211 of her remaining money on a windbreaker and a jacket, after which half her money was left.
- What fraction of her money did she spend on the blazer?
- The cost of the jacket is 15 the cost of the windbreaker. How much more does the windbreaker cost than the jacket?
Blazer |
Remaining amount |
|
Windbreaker |
Jacket |
Left |
$84 |
2 |
9 |
1x9 |
1x9 |
7 u |
2 u |
9 u |
(a)
The amount of money left is repeated. Make the numerators the same LCM of 1 and 9 is 9.
1x92x9 of total money =
911 of remaining amount
918 of total money =
911 of remaining amount
Fraction of her money that she spent on the blazer
=
BlazerTotal =
718 (b)
Cost of the blazer = 7 u
7 u = 84
1 u = 84 ÷ 7 = 12
Cost of the windbreaker and the jacket
= 2 u
= 2 x 12
= $24
Cost of the jacket = 1 p
Cost of the windbreaker = 5 p
Total cost of the jacket and the windbreaker
= 1 p + 5 p
= 6 p
6 p = 24
1 p = 24 ÷ 6 = 4
Amount that the windbreaker was more than the jacket
= 5 p - 1 p
= 4 p
= 4 x 4
= $16
Answer(s): (a)
718; (b) $16