Helen spent $60 on a blouse. She spent ²₇ of her remaining money on a blazer and a windbreaker, after which half her money was left.

1. What fraction of her money did she spend on the blouse?
2. The cost of the windbreaker is ¹₄ the cost of the blazer. How much more does the blazer cost than the windbreaker?

Blouse	Remaining amount
	Blazer	Windbreaker	Left
$60	2		5
1x5			1x5
3 u	2 u		5 u

(a)
The amount of money left is repeated. Make the numerators the same LCM of 1 and 5 is 5. 

1x52x5 of total money = 57 of remaining amount
510 of total money = 57 of remaining amount

Fraction of her money that she spent on the blouse
= ^Blouse_Total 
= ³₁₀ 

(b)
Cost of the blouse = 3 u

3 u = 60

1 u = 60 ÷ 3 = 20

Cost of the blazer and the windbreaker
= 2 u
= 2 x 20
= $40

Cost of the windbreaker = 1 p
Cost of the blazer = 4 p

Total cost of the windbreaker and the blazer 
= 1 p + 4 p
= 5 p

5 p = 40

1 p = 40 ÷ 5 = 8

Amount that the blazer was more than the windbreaker
= 4 p - 1 p
= 3 p
= 3 x 8
= $24

Answer(s): (a) ³₁₀; (b) $24