Helen spent $45 on a windbreaker. She spent
27 of her remaining money on a jacket and a dress, after which half her money was left.
- What fraction of her money did she spend on the windbreaker?
- The cost of the dress is 14 the cost of the jacket. How much more does the jacket cost than the dress?
Windbreaker |
Remaining amount |
|
Jacket |
Dress |
Left |
$45 |
2 |
5 |
1x5 |
1x5 |
3 u |
2 u |
5 u |
(a)
The amount of money left is repeated. Make the numerators the same LCM of 1 and 5 is 5.
1x52x5 of total money =
57 of remaining amount
510 of total money =
57 of remaining amount
Fraction of her money that she spent on the windbreaker
=
WindbreakerTotal =
310 (b)
Cost of the windbreaker = 3 u
3 u = 45
1 u = 45 ÷ 3 = 15
Cost of the jacket and the dress
= 2 u
= 2 x 15
= $30
Cost of the dress = 1 p
Cost of the jacket = 4 p
Total cost of the dress and the jacket
= 1 p + 4 p
= 5 p
5 p = 30
1 p = 30 ÷ 5 = 6
Amount that the jacket was more than the dress
= 4 p - 1 p
= 3 p
= 3 x 6
= $18
Answer(s): (a)
310; (b) $18