Helen spent $100 on a blouse. She spent
29 of her remaining money on a dress and a windbreaker, after which half her money was left.
- What fraction of her money did she spend on the blouse?
- The cost of the windbreaker is 14 the cost of the dress. How much more does the dress cost than the windbreaker?
Blouse |
Remaining amount |
|
Dress |
Windbreaker |
Left |
$100 |
2 |
7 |
1x7 |
1x7 |
5 u |
2 u |
7 u |
(a)
The amount of money left is repeated. Make the numerators the same LCM of 1 and 7 is 7.
1x72x7 of total money =
79 of remaining amount
714 of total money =
79 of remaining amount
Fraction of her money that she spent on the blouse
=
BlouseTotal =
514 (b)
Cost of the blouse = 5 u
5 u = 100
1 u = 100 ÷ 5 = 20
Cost of the dress and the windbreaker
= 2 u
= 2 x 20
= $40
Cost of the windbreaker = 1 p
Cost of the dress = 4 p
Total cost of the windbreaker and the dress
= 1 p + 4 p
= 5 p
5 p = 40
1 p = 40 ÷ 5 = 8
Amount that the dress was more than the windbreaker
= 4 p - 1 p
= 3 p
= 3 x 8
= $24
Answer(s): (a)
514; (b) $24