There were 256 pupils in a school. On the school anniversary,
56 of the girls and
45 of the boys came in yellow windbreakers. The rest came in red windbreakers. The number of boys who wore red windbreakers was twice of the girls who wore red windbreakers. How many pupils were in yellow windbreakers that day?
| Girls |
Boys |
Total |
| Yellow windbreakers |
Red windbreakers |
Yellow windbreakers |
Red windbreakers |
|
| 5 |
1 |
4x2 |
1x2 |
|
| |
1 |
|
2 |
|
| 5 u |
1 u |
8 u |
2 u |
16 u |
The number of boys who came in red windbreakers is repeated. Make the number of boys who came in red windbreakers the same. LCM of 1 and 2 is 2.
Total number of pupils
= 5 u + 1 u + 8 u + 2 u
= 16 u
16 u = 256
1 u = 256 ÷ 16 = 16
Number of pupils in yellow windbreakers
= 5 u + 8 u
= 13 u
= 13 x 16
= 208
Answer(s): 208
