Linda, Diana, Pierre and Kimberly shared some coins. Linda and Diana took
14 of the total number of coins while Pierre and Kimberly took the rest. Diana had twice as many coins as Linda and Kimberly had 36 coins. Given that Kimberly had twice as many coins as Diana, how many coins were there altogether?
Linda |
Diana |
Pierre |
Kimberly |
Total |
1x3 |
3x3 |
4x3 |
1 |
2 |
|
|
|
|
1x2 |
|
2x2 |
|
1 u |
2 u |
5 u |
4 u |
12 u |
Number of coins that Diana had is repeated. Make the number of coins that Diana had the same. LCM of 2 and 1 is 2.
Number of coins that Kimberly had = 4 u
4 u = 36
1 u = 36 ÷ 4 = 9
Total number of coins
= 12 u
= 12 x 9
= 108
Answer(s): 108