Julie, Xylia, Wesley and Anna shared some pens. Julie and Xylia took
15 of the total number of pens while Wesley and Anna took the rest. Xylia had twice as many pens as Julie and Anna had 44 pens. Given that Anna had twice as many pens as Xylia, how many pens were there altogether?
Julie |
Xylia |
Wesley |
Anna |
Total |
1x3 |
4x3 |
5x3 |
1 |
2 |
|
|
|
|
1x2 |
|
2x2 |
|
1 u |
2 u |
8 u |
4 u |
15 u |
Number of pens that Xylia had is repeated. Make the number of pens that Xylia had the same. LCM of 2 and 1 is 2.
Number of pens that Anna had = 4 u
4 u = 44
1 u = 44 ÷ 4 = 11
Total number of pens
= 15 u
= 15 x 11
= 165
Answer(s): 165