Shannon, Opal, Peter and Jade shared some beads. Shannon and Opal took
15 of the total number of beads while Peter and Jade took the rest. Opal had twice as many beads as Shannon and Jade had 12 beads. Given that Jade had twice as many beads as Opal, how many beads were there altogether?
| Shannon |
Opal |
Peter |
Jade |
Total |
| 1x3 |
4x3 |
5x3 |
| 1 |
2 |
|
|
|
| |
1x2 |
|
2x2 |
|
| 1 u |
2 u |
8 u |
4 u |
15 u |
Number of beads that Opal had is repeated. Make the number of beads that Opal had the same. LCM of 2 and 1 is 2.
Number of beads that Jade had = 4 u
4 u = 12
1 u = 12 ÷ 4 = 3
Total number of beads
= 15 u
= 15 x 3
= 45
Answer(s): 45
