Joelle, Jane, Simon and Emma shared some coins. Joelle and Jane took
16 of the total number of coins while Simon and Emma took the rest. Jane had thrice as many coins as Joelle and Emma had 18 coins. Given that Emma had twice as many coins as Jane, how many coins were there altogether?
Joelle |
Jane |
Simon |
Emma |
Total |
1x4 |
5x4 |
6x4 |
1 |
3 |
|
|
|
|
1x3 |
|
2x3 |
|
1 u |
3 u |
14 u |
6 u |
24 u |
Number of coins that Jane had is repeated. Make the number of coins that Jane had the same. LCM of 3 and 1 is 3.
Number of coins that Emma had = 6 u
6 u = 18
1 u = 18 ÷ 6 = 3
Total number of coins
= 24 u
= 24 x 3
= 72
Answer(s): 72