Sabrina, Cathy, Tommy and Linda shared some coins. Sabrina and Cathy took
14 of the total number of coins while Tommy and Linda took the rest. Cathy had twice as many coins as Sabrina and Linda had 36 coins. Given that Linda had twice as many coins as Cathy, how many coins were there altogether?
Sabrina |
Cathy |
Tommy |
Linda |
Total |
1x3 |
3x3 |
4x3 |
1 |
2 |
|
|
|
|
1x2 |
|
2x2 |
|
1 u |
2 u |
5 u |
4 u |
12 u |
Number of coins that Cathy had is repeated. Make the number of coins that Cathy had the same. LCM of 2 and 1 is 2.
Number of coins that Linda had = 4 u
4 u = 36
1 u = 36 ÷ 4 = 9
Total number of coins
= 12 u
= 12 x 9
= 108
Answer(s): 108