Marion, Victoria, Reggie and Yoko shared some coins. Marion and Victoria took
15 of the total number of coins while Reggie and Yoko took the rest. Victoria had twice as many coins as Marion and Yoko had 36 coins. Given that Yoko had twice as many coins as Victoria, how many coins were there altogether?
Marion |
Victoria |
Reggie |
Yoko |
Total |
1x3 |
4x3 |
5x3 |
1 |
2 |
|
|
|
|
1x2 |
|
2x2 |
|
1 u |
2 u |
8 u |
4 u |
15 u |
Number of coins that Victoria had is repeated. Make the number of coins that Victoria had the same. LCM of 2 and 1 is 2.
Number of coins that Yoko had = 4 u
4 u = 36
1 u = 36 ÷ 4 = 9
Total number of coins
= 15 u
= 15 x 9
= 135
Answer(s): 135