Esther, Hilda, Perry and Dana shared some beads. Esther and Hilda took
15 of the total number of beads while Perry and Dana took the rest. Hilda had thrice as many beads as Esther and Dana had 48 beads. Given that Dana had four times as many beads as Hilda, how many beads were there altogether?
| Esther |
Hilda |
Perry |
Dana |
Total |
| 1x4 |
4x4 |
5x4 |
| 1 |
3 |
|
|
|
| |
1x3 |
|
4x3 |
|
| 1 u |
3 u |
4 u |
12 u |
20 u |
Number of beads that Hilda had is repeated. Make the number of beads that Hilda had the same. LCM of 3 and 1 is 3.
Number of beads that Dana had = 12 u
12 u = 48
1 u = 48 ÷ 12 = 4
Total number of beads
= 20 u
= 20 x 4
= 80
Answer(s): 80
