Abi, Zoe, Asher and Xylia shared some pens. Abi and Zoe took
15 of the total number of pens while Asher and Xylia took the rest. Zoe had thrice as many pens as Abi and Xylia had 54 pens. Given that Xylia had twice as many pens as Zoe, how many pens were there altogether?
Abi |
Zoe |
Asher |
Xylia |
Total |
1x4 |
4x4 |
5x4 |
1 |
3 |
|
|
|
|
1x3 |
|
2x3 |
|
1 u |
3 u |
10 u |
6 u |
20 u |
Number of pens that Zoe had is repeated. Make the number of pens that Zoe had the same. LCM of 3 and 1 is 3.
Number of pens that Xylia had = 6 u
6 u = 54
1 u = 54 ÷ 6 = 9
Total number of pens
= 20 u
= 20 x 9
= 180
Answer(s): 180