Lucy, Cindy, Lee and Jane shared some coins. Lucy and Cindy took
15 of the total number of coins while Lee and Jane took the rest. Cindy had thrice as many coins as Lucy and Jane had 96 coins. Given that Jane had four times as many coins as Cindy, how many coins were there altogether?
Lucy |
Cindy |
Lee |
Jane |
Total |
1x4 |
4x4 |
5x4 |
1 |
3 |
|
|
|
|
1x3 |
|
4x3 |
|
1 u |
3 u |
4 u |
12 u |
20 u |
Number of coins that Cindy had is repeated. Make the number of coins that Cindy had the same. LCM of 3 and 1 is 3.
Number of coins that Jane had = 12 u
12 u = 96
1 u = 96 ÷ 12 = 8
Total number of coins
= 20 u
= 20 x 8
= 160
Answer(s): 160