Zoe, Jean, Bobby and Raeann shared some coins. Zoe and Jean took
15 of the total number of coins while Bobby and Raeann took the rest. Jean had four times as many coins as Zoe and Raeann had 48 coins. Given that Raeann had four times as many coins as Jean, how many coins were there altogether?
Zoe |
Jean |
Bobby |
Raeann |
Total |
1x5 |
4x5 |
5x5 |
1 |
4 |
|
|
|
|
1x4 |
|
4x4 |
|
1 u |
4 u |
4 u |
16 u |
25 u |
Number of coins that Jean had is repeated. Make the number of coins that Jean had the same. LCM of 4 and 1 is 4.
Number of coins that Raeann had = 16 u
16 u = 48
1 u = 48 ÷ 16 = 3
Total number of coins
= 25 u
= 25 x 3
= 75
Answer(s): 75