Kylie, Nicole, Will and Opal shared some coins. Kylie and Nicole took
16 of the total number of coins while Will and Opal took the rest. Nicole had four times as many coins as Kylie and Opal had 60 coins. Given that Opal had thrice as many coins as Nicole, how many coins were there altogether?
Kylie |
Nicole |
Will |
Opal |
Total |
1x5 |
5x5 |
6x5 |
1 |
4 |
|
|
|
|
1x4 |
|
3x4 |
|
1 u |
4 u |
13 u |
12 u |
30 u |
Number of coins that Nicole had is repeated. Make the number of coins that Nicole had the same. LCM of 4 and 1 is 4.
Number of coins that Opal had = 12 u
12 u = 60
1 u = 60 ÷ 12 = 5
Total number of coins
= 30 u
= 30 x 5
= 150
Answer(s): 150