Abi, Xylia, Harry and Julie shared some buttons. Abi and Xylia took
16 of the total number of buttons while Harry and Julie took the rest. Xylia had four times as many buttons as Abi and Julie had 24 buttons. Given that Julie had twice as many buttons as Xylia, how many buttons were there altogether?
Abi |
Xylia |
Harry |
Julie |
Total |
1x5 |
5x5 |
6x5 |
1 |
4 |
|
|
|
|
1x4 |
|
2x4 |
|
1 u |
4 u |
17 u |
8 u |
30 u |
Number of buttons that Xylia had is repeated. Make the number of buttons that Xylia had the same. LCM of 4 and 1 is 4.
Number of buttons that Julie had = 8 u
8 u = 24
1 u = 24 ÷ 8 = 3
Total number of buttons
= 30 u
= 30 x 3
= 90
Answer(s): 90