Opal, Penelope, Japheth and Yoko shared some beads. Opal and Penelope took
15 of the total number of beads while Japheth and Yoko took the rest. Penelope had four times as many beads as Opal and Yoko had 64 beads. Given that Yoko had twice as many beads as Penelope, how many beads were there altogether?
Opal |
Penelope |
Japheth |
Yoko |
Total |
1x5 |
4x5 |
5x5 |
1 |
4 |
|
|
|
|
1x4 |
|
2x4 |
|
1 u |
4 u |
12 u |
8 u |
25 u |
Number of beads that Penelope had is repeated. Make the number of beads that Penelope had the same. LCM of 4 and 1 is 4.
Number of beads that Yoko had = 8 u
8 u = 64
1 u = 64 ÷ 8 = 8
Total number of beads
= 25 u
= 25 x 8
= 200
Answer(s): 200