Emily, Abi, Ken and Yen shared some beads. Emily and Abi took
14 of the total number of beads while Ken and Yen took the rest. Abi had twice as many beads as Emily and Yen had 28 beads. Given that Yen had twice as many beads as Abi, how many beads were there altogether?
Emily |
Abi |
Ken |
Yen |
Total |
1x3 |
3x3 |
4x3 |
1 |
2 |
|
|
|
|
1x2 |
|
2x2 |
|
1 u |
2 u |
5 u |
4 u |
12 u |
Number of beads that Abi had is repeated. Make the number of beads that Abi had the same. LCM of 2 and 1 is 2.
Number of beads that Yen had = 4 u
4 u = 28
1 u = 28 ÷ 4 = 7
Total number of beads
= 12 u
= 12 x 7
= 84
Answer(s): 84