Jane, Julie, Sam and Cathy shared some stickers. Jane and Julie took
15 of the total number of stickers while Sam and Cathy took the rest. Julie had twice as many stickers as Jane and Cathy had 40 stickers. Given that Cathy had twice as many stickers as Julie, how many stickers were there altogether?
| Jane |
Julie |
Sam |
Cathy |
Total |
| 1x3 |
4x3 |
5x3 |
| 1 |
2 |
|
|
|
| |
1x2 |
|
2x2 |
|
| 1 u |
2 u |
8 u |
4 u |
15 u |
Number of stickers that Julie had is repeated. Make the number of stickers that Julie had the same. LCM of 2 and 1 is 2.
Number of stickers that Cathy had = 4 u
4 u = 40
1 u = 40 ÷ 4 = 10
Total number of stickers
= 15 u
= 15 x 10
= 150
Answer(s): 150
