Julian bought some coupons for a funfair. He used
47 of the coupons on games and
37 of the remainder on food. He bought another 99 coupons and had 25 more coupons than he had at first. How many coupons did he have at first?
| Games |
Remainder |
Bought |
Total |
4x7 =
28 u |
3x7 =
21 u |
|
7x7 =
49 u |
| |
Food |
Left |
|
|
| |
3x3 |
4x3 |
|
|
| 28 u |
9 u |
12 u |
99 |
49 u |
The remaining number of coupons before Julian bought another 99 coupons is repeated. Make the remaining number of coupons the same. LCM of 3 and 7 is 21.
Total number of coupons at first = 49 u
Total number of coupons in the end = 12 u + 99
Number of coupons left was 25 more than the number of coupons at first.
49 u + 25 = 12 u + 99
49 u - 12 u = 99 - 25
37 u = 74
1 u = 74 ÷ 37 = 2
Total number of coupons at first
= 49 u
= 49 x 2
= 98
Answer(s): 98
