Luke bought some coupons for a funfair. He used
25 of the coupons on games and
35 of the remainder on food. He bought another 87 coupons and had 49 more coupons than he had at first. How many coupons did he have at first?
| Games |
Remainder |
Bought |
Total |
2x5 =
10 u |
3x5 =
15 u |
|
5x5 =
25 u |
| |
Food |
Left |
|
|
| |
3x3 |
2x3 |
|
|
| 10 u |
9 u |
6 u |
87 |
25 u |
The remaining number of coupons before Luke bought another 87 coupons is repeated. Make the remaining number of coupons the same. LCM of 3 and 5 is 15.
Total number of coupons at first = 25 u
Total number of coupons in the end = 6 u + 87
Number of coupons left was 49 more than the number of coupons at first.
25 u + 49 = 6 u + 87
25 u - 6 u = 87 - 49
19 u = 38
1 u = 38 ÷ 19 = 2
Total number of coupons at first
= 25 u
= 25 x 2
= 50
Answer(s): 50
