Simon bought some coupons for a funfair. He used
37 of the coupons on games and
35 of the remainder on food. He bought another 89 coupons and had 35 more coupons than he had at first. How many coupons did he have at first?
| Games |
Remainder |
Bought |
Total |
3x5 =
15 u |
4x5 =
20 u |
|
7x5 =
35 u |
| |
Food |
Left |
|
|
| |
3x4 |
2x4 |
|
|
| 15 u |
12 u |
8 u |
89 |
35 u |
The remaining number of coupons before Simon bought another 89 coupons is repeated. Make the remaining number of coupons the same. LCM of 4 and 5 is 20.
Total number of coupons at first = 35 u
Total number of coupons in the end = 8 u + 89
Number of coupons left was 35 more than the number of coupons at first.
35 u + 35 = 8 u + 89
35 u - 8 u = 89 - 35
27 u = 54
1 u = 54 ÷ 27 = 2
Total number of coupons at first
= 35 u
= 35 x 2
= 70
Answer(s): 70
