Reggie bought some coupons for a funfair. He used
27 of the coupons on games and
38 of the remainder on food. He bought another 98 coupons and had 5 more coupons than he had at first. How many coupons did he have at first?
| Games |
Remainder |
Bought |
Total |
2x8 =
16 u |
5x8 =
40 u |
|
7x8 =
56 u |
| |
Food |
Left |
|
|
| |
3x5 |
5x5 |
|
|
| 16 u |
15 u |
25 u |
98 |
56 u |
The remaining number of coupons before Reggie bought another 98 coupons is repeated. Make the remaining number of coupons the same. LCM of 5 and 8 is 40.
Total number of coupons at first = 56 u
Total number of coupons in the end = 25 u + 98
Number of coupons left was 5 more than the number of coupons at first.
56 u + 5 = 25 u + 98
56 u - 25 u = 98 - 5
31 u = 93
1 u = 93 ÷ 31 = 3
Total number of coupons at first
= 56 u
= 56 x 3
= 168
Answer(s): 168
