Dylan bought some coupons for a funfair. He used
25 of the coupons on food and
58 of the remainder on games. He bought another 82 coupons and had 20 more coupons than he had at first. How many coupons did he have at first?
| Food |
Remainder |
Bought |
Total |
2x8 =
16 u |
3x8 =
24 u |
|
5x8 =
40 u |
| |
Games |
Left |
|
|
| |
5x3 |
3x3 |
|
|
| 16 u |
15 u |
9 u |
82 |
40 u |
The remaining number of coupons before Dylan bought another 82 coupons is repeated. Make the remaining number of coupons the same. LCM of 3 and 8 is 24.
Total number of coupons at first = 40 u
Total number of coupons in the end = 9 u + 82
Number of coupons left was 20 more than the number of coupons at first.
40 u + 20 = 9 u + 82
40 u - 9 u = 82 - 20
31 u = 62
1 u = 62 ÷ 31 = 2
Total number of coupons at first
= 40 u
= 40 x 2
= 80
Answer(s): 80
