Eric bought some coupons for a funfair. He used
35 of the coupons on food and
37 of the remainder on games. He bought another 89 coupons and had 35 more coupons than he had at first. How many coupons did he have at first?
| Food |
Remainder |
Bought |
Total |
3x7 =
21 u |
2x7 =
14 u |
|
5x7 =
35 u |
| |
Games |
Left |
|
|
| |
3x2 |
4x2 |
|
|
| 21 u |
6 u |
8 u |
89 |
35 u |
The remaining number of coupons before Eric bought another 89 coupons is repeated. Make the remaining number of coupons the same. LCM of 2 and 7 is 14.
Total number of coupons at first = 35 u
Total number of coupons in the end = 8 u + 89
Number of coupons left was 35 more than the number of coupons at first.
35 u + 35 = 8 u + 89
35 u - 8 u = 89 - 35
27 u = 54
1 u = 54 ÷ 27 = 2
Total number of coupons at first
= 35 u
= 35 x 2
= 70
Answer(s): 70
