Justin bought some coupons for a funfair. He used
37 of the coupons on food and
35 of the remainder on games. He bought another 84 coupons and had 3 more coupons than he had at first. How many coupons did he have at first?
| Food |
Remainder |
Bought |
Total |
3x5 =
15 u |
4x5 =
20 u |
|
7x5 =
35 u |
| |
Games |
Left |
|
|
| |
3x4 |
2x4 |
|
|
| 15 u |
12 u |
8 u |
84 |
35 u |
The remaining number of coupons before Justin bought another 84 coupons is repeated. Make the remaining number of coupons the same. LCM of 4 and 5 is 20.
Total number of coupons at first = 35 u
Total number of coupons in the end = 8 u + 84
Number of coupons left was 3 more than the number of coupons at first.
35 u + 3 = 8 u + 84
35 u - 8 u = 84 - 3
27 u = 81
1 u = 81 ÷ 27 = 3
Total number of coupons at first
= 35 u
= 35 x 3
= 105
Answer(s): 105
