Michael bought some coupons for a funfair. He used
25 of the coupons on games and
35 of the remainder on food. He bought another 60 coupons and had 3 more coupons than he had at first. How many coupons did he have at first?
| Games |
Remainder |
Bought |
Total |
2x5 =
10 u |
3x5 =
15 u |
|
5x5 =
25 u |
| |
Food |
Left |
|
|
| |
3x3 |
2x3 |
|
|
| 10 u |
9 u |
6 u |
60 |
25 u |
The remaining number of coupons before Michael bought another 60 coupons is repeated. Make the remaining number of coupons the same. LCM of 3 and 5 is 15.
Total number of coupons at first = 25 u
Total number of coupons in the end = 6 u + 60
Number of coupons left was 3 more than the number of coupons at first.
25 u + 3 = 6 u + 60
25 u - 6 u = 60 - 3
19 u = 57
1 u = 57 ÷ 19 = 3
Total number of coupons at first
= 25 u
= 25 x 3
= 75
Answer(s): 75
