John bought some coupons for a funfair. He used
35 of the coupons on food and
25 of the remainder on games. He bought another 46 coupons and had 8 more coupons than he had at first. How many coupons did he have at first?
Food |
Remainder |
Bought |
Total |
3x5 = 15 u |
2x5 = 10 u |
|
5x5 = 25 u |
|
Games |
Left |
|
|
|
2x2 |
3x2 |
|
|
15 u |
4 u |
6 u |
46 |
25 u |
The remaining number of coupons before John bought another 46 coupons is repeated. Make the remaining number of coupons the same. LCM of 2 and 5 is 10.
Total number of coupons at first = 25 u
Total number of coupons in the end = 6 u + 46
Number of coupons left was 8 more than the number of coupons at first.
25 u + 8 = 6 u + 46
25 u - 6 u = 46 - 8
19 u = 38
1 u = 38 ÷ 19 = 2
Total number of coupons at first
= 25 u
= 25 x 2
= 50
Answer(s): 50