Harry bought some coupons for a funfair. He used
37 of the coupons on games and
27 of the remainder on food. He bought another 97 coupons and had 39 more coupons than he had at first. How many coupons did he have at first?
| Games |
Remainder |
Bought |
Total |
3x7 =
21 u |
4x7 =
28 u |
|
7x7 =
49 u |
| |
Food |
Left |
|
|
| |
2x4 |
5x4 |
|
|
| 21 u |
8 u |
20 u |
97 |
49 u |
The remaining number of coupons before Harry bought another 97 coupons is repeated. Make the remaining number of coupons the same. LCM of 4 and 7 is 28.
Total number of coupons at first = 49 u
Total number of coupons in the end = 20 u + 97
Number of coupons left was 39 more than the number of coupons at first.
49 u + 39 = 20 u + 97
49 u - 20 u = 97 - 39
29 u = 58
1 u = 58 ÷ 29 = 2
Total number of coupons at first
= 49 u
= 49 x 2
= 98
Answer(s): 98
