Andy bought some coupons for a funfair. He used
25 of the coupons on games and
27 of the remainder on food. He bought another 48 coupons and had 8 more coupons than he had at first. How many coupons did he have at first?
| Games |
Remainder |
Bought |
Total |
2x7 =
14 u |
3x7 =
21 u |
|
5x7 =
35 u |
| |
Food |
Left |
|
|
| |
2x3 |
5x3 |
|
|
| 14 u |
6 u |
15 u |
48 |
35 u |
The remaining number of coupons before Andy bought another 48 coupons is repeated. Make the remaining number of coupons the same. LCM of 3 and 7 is 21.
Total number of coupons at first = 35 u
Total number of coupons in the end = 15 u + 48
Number of coupons left was 8 more than the number of coupons at first.
35 u + 8 = 15 u + 48
35 u - 15 u = 48 - 8
20 u = 40
1 u = 40 ÷ 20 = 2
Total number of coupons at first
= 35 u
= 35 x 2
= 70
Answer(s): 70
