Sean bought some coupons for a funfair. He used
37 of the coupons on food and
35 of the remainder on games. He bought another 92 coupons and had 38 more coupons than he had at first. How many coupons did he have at first?
| Food |
Remainder |
Bought |
Total |
3x5 =
15 u |
4x5 =
20 u |
|
7x5 =
35 u |
| |
Games |
Left |
|
|
| |
3x4 |
2x4 |
|
|
| 15 u |
12 u |
8 u |
92 |
35 u |
The remaining number of coupons before Sean bought another 92 coupons is repeated. Make the remaining number of coupons the same. LCM of 4 and 5 is 20.
Total number of coupons at first = 35 u
Total number of coupons in the end = 8 u + 92
Number of coupons left was 38 more than the number of coupons at first.
35 u + 38 = 8 u + 92
35 u - 8 u = 92 - 38
27 u = 54
1 u = 54 ÷ 27 = 2
Total number of coupons at first
= 35 u
= 35 x 2
= 70
Answer(s): 70
