Bobby bought some coupons for a funfair. He used
37 of the coupons on food and
27 of the remainder on games. He bought another 70 coupons and had 12 more coupons than he had at first. How many coupons did he have at first?
| Food |
Remainder |
Bought |
Total |
3x7 =
21 u |
4x7 =
28 u |
|
7x7 =
49 u |
| |
Games |
Left |
|
|
| |
2x4 |
5x4 |
|
|
| 21 u |
8 u |
20 u |
70 |
49 u |
The remaining number of coupons before Bobby bought another 70 coupons is repeated. Make the remaining number of coupons the same. LCM of 4 and 7 is 28.
Total number of coupons at first = 49 u
Total number of coupons in the end = 20 u + 70
Number of coupons left was 12 more than the number of coupons at first.
49 u + 12 = 20 u + 70
49 u - 20 u = 70 - 12
29 u = 58
1 u = 58 ÷ 29 = 2
Total number of coupons at first
= 49 u
= 49 x 2
= 98
Answer(s): 98
