David bought some coupons for a funfair. He used
25 of the coupons on games and
35 of the remainder on food. He bought another 63 coupons and had 6 more coupons than he had at first. How many coupons did he have at first?
Games |
Remainder |
Bought |
Total |
2x5 = 10 u |
3x5 = 15 u |
|
5x5 = 25 u |
|
Food |
Left |
|
|
|
3x3 |
2x3 |
|
|
10 u |
9 u |
6 u |
63 |
25 u |
The remaining number of coupons before David bought another 63 coupons is repeated. Make the remaining number of coupons the same. LCM of 3 and 5 is 15.
Total number of coupons at first = 25 u
Total number of coupons in the end = 6 u + 63
Number of coupons left was 6 more than the number of coupons at first.
25 u + 6 = 6 u + 63
25 u - 6 u = 63 - 6
19 u = 57
1 u = 57 ÷ 19 = 3
Total number of coupons at first
= 25 u
= 25 x 3
= 75
Answer(s): 75