Gabriel bought some coupons for a funfair. He used
35 of the coupons on food and
37 of the remainder on games. He bought another 99 coupons and had 18 more coupons than he had at first. How many coupons did he have at first?
| Food |
Remainder |
Bought |
Total |
3x7 =
21 u |
2x7 =
14 u |
|
5x7 =
35 u |
| |
Games |
Left |
|
|
| |
3x2 |
4x2 |
|
|
| 21 u |
6 u |
8 u |
99 |
35 u |
The remaining number of coupons before Gabriel bought another 99 coupons is repeated. Make the remaining number of coupons the same. LCM of 2 and 7 is 14.
Total number of coupons at first = 35 u
Total number of coupons in the end = 8 u + 99
Number of coupons left was 18 more than the number of coupons at first.
35 u + 18 = 8 u + 99
35 u - 8 u = 99 - 18
27 u = 81
1 u = 81 ÷ 27 = 3
Total number of coupons at first
= 35 u
= 35 x 3
= 105
Answer(s): 105
