Cole bought some coupons for a funfair. He used
47 of the coupons on games and
38 of the remainder on food. He bought another 85 coupons and had 3 more coupons than he had at first. How many coupons did he have at first?
| Games |
Remainder |
Bought |
Total |
4x8 =
32 u |
3x8 =
24 u |
|
7x8 =
56 u |
| |
Food |
Left |
|
|
| |
3x3 |
5x3 |
|
|
| 32 u |
9 u |
15 u |
85 |
56 u |
The remaining number of coupons before Cole bought another 85 coupons is repeated. Make the remaining number of coupons the same. LCM of 3 and 8 is 24.
Total number of coupons at first = 56 u
Total number of coupons in the end = 15 u + 85
Number of coupons left was 3 more than the number of coupons at first.
56 u + 3 = 15 u + 85
56 u - 15 u = 85 - 3
41 u = 82
1 u = 82 ÷ 41 = 2
Total number of coupons at first
= 56 u
= 56 x 2
= 112
Answer(s): 112
