Liam bought some coupons for a funfair. He used
35 of the coupons on food and
27 of the remainder on games. He bought another 84 coupons and had 9 more coupons than he had at first. How many coupons did he have at first?
| Food |
Remainder |
Bought |
Total |
3x7 =
21 u |
2x7 =
14 u |
|
5x7 =
35 u |
| |
Games |
Left |
|
|
| |
2x2 |
5x2 |
|
|
| 21 u |
4 u |
10 u |
84 |
35 u |
The remaining number of coupons before Liam bought another 84 coupons is repeated. Make the remaining number of coupons the same. LCM of 2 and 7 is 14.
Total number of coupons at first = 35 u
Total number of coupons in the end = 10 u + 84
Number of coupons left was 9 more than the number of coupons at first.
35 u + 9 = 10 u + 84
35 u - 10 u = 84 - 9
25 u = 75
1 u = 75 ÷ 25 = 3
Total number of coupons at first
= 35 u
= 35 x 3
= 105
Answer(s): 105
