Fred bought some coupons for a funfair. He used
37 of the coupons on food and
25 of the remainder on games. He bought another 76 coupons and had 30 more coupons than he had at first. How many coupons did he have at first?
| Food |
Remainder |
Bought |
Total |
3x5 =
15 u |
4x5 =
20 u |
|
7x5 =
35 u |
| |
Games |
Left |
|
|
| |
2x4 |
3x4 |
|
|
| 15 u |
8 u |
12 u |
76 |
35 u |
The remaining number of coupons before Fred bought another 76 coupons is repeated. Make the remaining number of coupons the same. LCM of 4 and 5 is 20.
Total number of coupons at first = 35 u
Total number of coupons in the end = 12 u + 76
Number of coupons left was 30 more than the number of coupons at first.
35 u + 30 = 12 u + 76
35 u - 12 u = 76 - 30
23 u = 46
1 u = 46 ÷ 23 = 2
Total number of coupons at first
= 35 u
= 35 x 2
= 70
Answer(s): 70
