Carl bought some coupons for a funfair. He used
35 of the coupons on games and
25 of the remainder on food. He bought another 85 coupons and had 9 more coupons than he had at first. How many coupons did he have at first?
Games |
Remainder |
Bought |
Total |
3x5 = 15 u |
2x5 = 10 u |
|
5x5 = 25 u |
|
Food |
Left |
|
|
|
2x2 |
3x2 |
|
|
15 u |
4 u |
6 u |
85 |
25 u |
The remaining number of coupons before Carl bought another 85 coupons is repeated. Make the remaining number of coupons the same. LCM of 2 and 5 is 10.
Total number of coupons at first = 25 u
Total number of coupons in the end = 6 u + 85
Number of coupons left was 9 more than the number of coupons at first.
25 u + 9 = 6 u + 85
25 u - 6 u = 85 - 9
19 u = 76
1 u = 76 ÷ 19 = 4
Total number of coupons at first
= 25 u
= 25 x 4
= 100
Answer(s): 100