Marion spent ³₅ of her money on 3 correction tapes and 6 highlighters. The cost of one highlighter was twice the cost of one correction tape. She bought some more highlighters with ¹₅ of her remaining money. How many highlighters did Marion buy altogether?

3 correction tapes and 6 highlighters	Remaining amount
3x5	2x5
	More highlighters	Left
	1x2	4x2
15 p	2 p	8 p

Cost of 1 correction tape = 1 u
Cost of 1 highlighter = 2 u

Cost of 3 correction tapes = 3 x 1 u = 3 u
Cost of 6 highlighters = 6 x 2 u = 12 u

Total cost of 3 correction tapes and 6 highlighters
= 3 u + 12 u
= 15 u

15 p = 15 u

1 p = 15 ÷ 15 = 1 u

Amount that Marion used to buy more highlighters
= 2 p
= 2 x 1 u
= 2 u

Number of more highlighters that Marion bought
= 2 u ÷ 2 u
= 1

Total number of highlighters that Marion bought
= 6 + 1
= 7

Answer(s): 7