Hazel spent
25 of her money on 3 pencils and 9 correction tapes. The cost of one correction tape was thrice the cost of one pencil. She bought some more correction tapes with
15 of her remaining money. How many correction tapes did Hazel buy altogether?
3 pencils and 9 correction tapes |
Remaining amount |
2x5 |
3x5 |
|
More correction tapes |
Left |
|
1x3 |
4x3 |
10 p |
3 p |
12 p |
Cost of 1 pencil = 1 u
Cost of 1 correction tape = 3 u
Cost of 3 pencils = 3 x 1 u = 3 u
Cost of 9 correction tapes = 9 x 3 u = 27 u
Total cost of 3 pencils and 9 correction tapes
= 3 u + 27 u
= 30 u
10 p = 30 u
1 p = 30 ÷ 10 = 3 u
Amount that Hazel used to buy more correction tapes
= 3 p
= 3 x 3 u
= 9 u
Number of more correction tapes that Hazel bought
= 9 u ÷ 3 u
= 3
Total number of correction tapes that Hazel bought
= 9 + 3
= 12
Answer(s): 12