Linda spent
58 of her money on 10 pencils and 5 correction tapes. The cost of one correction tape was twice the cost of one pencil. She bought some more correction tapes with
16 of her remaining money. How many correction tapes did Linda buy altogether?
10 pencils and 5 correction tapes |
Remaining amount |
5x2 |
3x2 |
|
More correction tapes |
Left |
|
1x1 |
5x1 |
10 p |
1 p |
5 p |
Cost of 1 pencil = 1 u
Cost of 1 correction tape = 2 u
Cost of 10 pencils = 10 x 1 u = 10 u
Cost of 5 correction tapes = 5 x 2 u = 10 u
Total cost of 10 pencils and 5 correction tapes
= 10 u + 10 u
= 20 u
10 p = 20 u
1 p = 20 ÷ 10 = 2 u
Amount that Linda used to buy more correction tapes
= 1 p
= 1 x 2 u
= 2 u
Number of more correction tapes that Linda bought
= 2 u ÷ 2 u
= 1
Total number of correction tapes that Linda bought
= 5 + 1
= 6
Answer(s): 6