Penelope spent
37 of her money on 8 pens and 5 highlighters. The cost of one highlighter was twice the cost of one pen. She bought some more highlighters with
16 of her remaining money. How many highlighters did Penelope buy altogether?
8 pens and
5 highlighters |
Remaining amount |
| 3x3 |
4x3 |
| |
More highlighters |
Left |
| |
1x2 |
5x2 |
| 9 p |
2 p |
10 p |
Cost of 1 pen = 1 u
Cost of 1 highlighter = 2 u
Cost of 8 pens = 8 x 1 u = 8 u
Cost of 5 highlighters = 5 x 2 u = 10 u
Total cost of 8 pens and 5 highlighters
= 8 u + 10 u
= 18 u
9 p = 18 u
1 p = 18 ÷ 9 = 2 u
Amount that Penelope used to buy more highlighters
= 2 p
= 2 x 2 u
= 4 u
Number of more highlighters that Penelope bought
= 4 u ÷ 2 u
= 2
Total number of highlighters that Penelope bought
= 5 + 2
= 7
Answer(s): 7
